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The Maglev Train at Shanghai is the first commercial Maglev train in the world. Its highest speed is 430 km/h. It links the eastern region of Putong and the Pudong International Airport in eight minutes. The length of the railway is 30km.(a) The average speed of the train is 86.4km/h(b) Compare the speed in (a)... 顯示更多 The Maglev Train at Shanghai is the first commercial Maglev train in the world. Its highest speed is 430 km/h. It links the eastern region of Putong and the Pudong International Airport in eight minutes. The length of the railway is 30km. (a) The average speed of the train is 86.4km/h (b) Compare the speed in (a) with the maximum speed of the train. Give a reson of the discrepancy. (c) Just before starting: 11:01:58 0km/h Just after it reaches the highest speed: 11:05:45 431km/h Find the average acceleration of the train during the instances shown

最佳解答:

1. As the speed is incresed from zero to max. (430) and then decreased to zero, so the average is different from max. 2. v=u+at v- speed = 431 u - inital speed = 0 t - time taken = 3 minutes 47 seconds. so, average acceleration a = (v-u)/t = 431*3600/227 (km/h^2) = 6835

其他解答:8758B59A7FA1EEA7