標題:
HCF of 270,405
發問:
Find the HCF of 270,405
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最佳解答:
135 bcos 270 = 135*2 405 = 135*3 2008-12-18 23:45:36 補充： Method of doing: 5 | 270 405 __________ 9 | 54 81 __________ 3 | 6 9 __________ 2 3 HCF = 5*9*3 = 135 2008-12-18 23:56:41 補充： 有點兒移位 = = 但方法是兩數同時除它們的任意一個公因數 (240/5 & 405/5) 然後兩數被除後產生的商(54 & 81)，再用兩個商的任意一個公因數去除 (54/9 & 81/9) 所產的新的兩個商(6 & 9)，又再用新的兩個商的任意一個公因數去除(6/3 & 9/3) 如是者，直至最後的兩個商互質 (2 & 3，只可被 1 同時除盡) 最後將所有除數相乘 (5*9*3) 就是 HCF 了 2008-12-19 00:00:35 補充： Method of doing: 5 |....270.......405 ...____________ 9 |......54.........81 ...____________ 3 |........6...........9 ...____________ ............2.......... 3 HCF = 5*9*3 = 135 看的時候把點踢走吧~
其他解答:
Firstly, factorize 270 and 405 270=2 ． 3^3 ． 5 405=3 ． 3^3 ． 5 If we want to find the HCF of them, we only need to take out their common factors (公因數） =3^3 ． 5 =27 ． 5 =135|||||H.C.F. of 270 and 405 is 135.Because 270 F. has 1,2,3,5,6,9,10,15,1 8,27,30,45,54,90,135,270.405 F. has 1,3,5,9,15,27,45,81,135,405. They C.F. has 1,3,5,9,15,27,45,81,135.So,they H.C.F. is 135.|||||We can use the basic method: wirte 270 and 405 into their prime factorizations by short division 270= 2 x 3^3 x 5 405=3^4 x 5 hence HCF of 270 and 405 = 3^3 x 5 = 1358758B59A7FA1EEA7
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